Question

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Answer 1

HCF OF 592 and 252 :

592 = 252 × 2 + 88

252 = 88 × 2 + 76

88 = 76 × 1 + 12

76 = 12 × 6 + 4

12 = 4 × 3 + 0

Hence, HCF = 4

Now, 4 = 76 - 12 × 6

4 = 76 - (88 - 76 ) × 6

4 = 76 × 7 - 88 × 6

4 =  (252 - 88 × 2) × 7 - 88 × 6

4 = 252 × 7 - 88 × 20

4 = 252 × 7 - (592 - 252 × 2) × 20

4 = 252 × 47 - 592 × 20

4 = 252 (47) - 592 (20)

4 = 252 (47) + 592 (-20)

Hence 4 = 592m + 252n where,

m = (-20) and n = 47

Hence the value of m and n are :

m = (-20) and n = 47

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Answer 2

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@vaibhavhoax