Math, asked by mks6195, 11 months ago

here is ur question.......... ​

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Answers

Answered by aparnaachuthath7
1

Answer: I hope the answer is 693

Step-by-step explanation: since ones place is given as 3 and hundreds place is 2times ones place so 6 and tens place is the sum of hundreds and ones 6+3=9 so I hope this answer is correct

Answered by ridhima6rihi4
0

Answer:

the no is 693.

Step-by-step explanation:

Let hundreds digit be x , tens digit be y and ones digit be z.

Given,

Ones digit = 3 (z)

Now,

Condition - 1

x = 2z

  = 2 * 3

  = 6

Condition - 2

y = x + z

  = 6 + 3

  = 9

Then,

The required no = 100x + 10y + z

                           = 100 * 6 + 10 * 9 + 3

                           = 600 + 90 + 3

                           = 693

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