here is ur question..........
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Answered by
1
Answer: I hope the answer is 693
Step-by-step explanation: since ones place is given as 3 and hundreds place is 2times ones place so 6 and tens place is the sum of hundreds and ones 6+3=9 so I hope this answer is correct
Answered by
0
Answer:
the no is 693.
Step-by-step explanation:
Let hundreds digit be x , tens digit be y and ones digit be z.
Given,
Ones digit = 3 (z)
Now,
Condition - 1
x = 2z
= 2 * 3
= 6
Condition - 2
y = x + z
= 6 + 3
= 9
Then,
The required no = 100x + 10y + z
= 100 * 6 + 10 * 9 + 3
= 600 + 90 + 3
= 693
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