Question

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Answer 1

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⭐Mahir⭐

Answer 2

\text{AgI}(s)\;{\rightleftharpoons}\;\text{Ag}^{+}(aq)\;+\;\text{I}^{-}(aq)\;\;\;\;\;\;\;K_{\text{sp}} = [\text{Ag}^{+}][\text{I}^{-}]

\text{CaCO}_3(s)\;{\rightleftharpoons}\;\text{Ca}^{2+}(aq)\;+\;\text{CO}_3^{\;\;2-}(aq)\;\;\;\;\;\;\;K_{\text{sp}} = [\text{Ca}^{2+}][\text{CO}_3^{\;\;2-}]

\text{Mg(OH)}_2(s)\;{\rightleftharpoons}\;\text{Mg}^{2+}(aq)\;+\;2\text{OH}^{-}(aq)\;\;\;\;\;\;\;K_{\text{sp}} = [\text{Mg}^{2+}][\text{OH}^{-}]^2

(d) \text{Mg(NH}_4)\text{PO}_4(s)\;{\rightleftharpoons}\;\text{Mg}^{2+}(aq)\;+\;\text{NH}_4^{\;\;+}(aq)\;+\;\text{PO}_4^{\;\;3-}(aq)\;\;\;\;\;\;\;K_{\text{sp}} = [\text{Mg}^{2+}][\text{NH}_4^{\;\;+}][\text{PO}_4^{\;\;3-}]

\text{Ca}_5(\text{PO}_4)3\text{OH}(s)\;{\rightleftharpoons}\;5\text{Ca}^{2+}(aq)\;+\;3\text{PO}_4^{\;\;3-}(aq)\;+\;\text{OH}^{-}(aq)\;\;\;\;\;\;\;K_{\text{sp}} = [\text{Ca}^{2+}]^5[\text{PO}_4^{\;\;3-}]^3[\text{OH}^{-}]

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