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▶️ A car moving at 40km/h is to be stopped by applying brakes in the next 4•0 m. if the car weighs 2000 kg what average force must be applied on it?
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U=40km/h
=40000/3600
=11.11m/s
m=2000kg
v=0
s=4m
acceleration=(v^2-u^2)/2s
=(0-123.43)/8
=15.42m/s^2
so breaking force(F)=ma
=(2000)(15.42)
=30840
=(3.08) (10^4)N
=40000/3600
=11.11m/s
m=2000kg
v=0
s=4m
acceleration=(v^2-u^2)/2s
=(0-123.43)/8
=15.42m/s^2
so breaking force(F)=ma
=(2000)(15.42)
=30840
=(3.08) (10^4)N
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