Question

here is your question class 11 physics​

Answer 1

Step-by-step explanation:

Total distance travelled = 23 km

Total time taken = 28 min = 28 / 60 h

∴ Average speed of the taxi = Total disttance travelled / Total time taken

= 23 / (28/60) = 49.29 km/h

(b) Distance between the hotel and the station = 10 km = Displacement of the car

∴ Average velocity = 10 / (28/60) = 21.43 km/h

Therefore, the two physical quantities (averge speed and average velocity) are not equal

Answer 2

SOLUTION

A passenger arriving in a newb town wishes to go from the station to a hotel located 10 km away on a straight road from the station.

(a).Total distance travelled= 23km

Total time taken= 28minutes

$= > \frac{28}{60} hr.$

∴Average speed of the taxi

$= > \frac{Total \: distance \: travelled}{Total \: time \: taken}$

$= > \frac{23}{ (\frac{28}{60}) } = 49.29km \: h$

(b).Distance between the hotel & the station= 10km

& It is displacement of the car.

∴Average Velocity

$= > \frac{10}{ \frac{28}{60} } = 21.43km \: h$

Therefore,

The two physical quantities (average speed & average velocity) are not equal.

Hope it helps ☺️