Math, asked by avnitkar, 11 months ago

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Answered by Anonymous
8

refer to the attachment

here is your answer

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Answered by Anonymous
5

Hii

you are welcome in my ans

let radius of wire A be x

initial length be a

yA = 9.8*a/πx^2*1

let change in length of B =dt

yB= 1.5*a*4*9.8*16/πx^2*25dt

YA =yB

9.8= 1.5*4*9.8*16/25dt

dt = 6*9.8*16/9.8*25

dt = 96/25

dt = 3.84mm

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Hope it may helps you

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