Question

here is your question in the attachment ​

Answer 1

Number of collisions

NC =

$\frac{1}{6} \times ( \frac{p}{kt} ) \times \sqrt{ \frac{3rt}{m} } = \frac{1}{6} \frac{p}{k} \sqrt{ \frac{3r}{mt} } \\ \frac{1}{6} \times \frac{1.013 \times 10 ^{5} }{1.38 \times 10 ^{ - 23} } \sqrt{ \frac{3 \times 8.3}{(32 \times 10^{ - 3} )(300)} } \\ = 1.97 \times 10 ^{27} m ^{2} s ^{ - 1}$

Answer 2

hey mate

here is your answer