Question

here is your question

the standard enthalpy changes for the transition of liquid water to steam is 40.8 KJ Mol -1 at hundred degree Celsius calculate triangle s degree for the change ​

Answer 1

◇S°vap = ◇H°vap/Tb

40.8kJ mol^-1/(100+273)K

= 109.383 JK^-1 mol ^-1

Answer 2

✌✌hey mate✌✌

◇s°v Ap=◇H°vAp/TV

40.8kj mol^-1/(100+273)I

->109.383jk^-1mol^-1<-