here it do it guys plzz
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Let a and b are the numbers.Then a+b is 12 and ab is 35.
a+b/ab = 12/35
1/a+1/b = 12/35
a+b/ab = 12/35
1/a+1/b = 12/35
Avm21:
that intellengency u have showed to us both by giving answer.... ha ha ha
just joking my friend
give a pic of the answer page in ur book
ok
now check the answer it was a small calculation mistakr
oooo
check my answer
right bro
ok bye
Answered by
1
let the 1st no. be x then 2nd no. =(12-x) since there sum is 12.
Now, A/q
x×y =35
=>x=35/y. (y is the second no.)
=>x=35/(12-x)=>12x-x^2-35=0
=>-x^2+12x-35=0
=>-x^2-7x-5x-35=0
=>-x(x+7)-5(x+7)=0
=>(x+7)(x-5)=0
=>x+7=0. or. x-5=0
= x=-7. or. x=5
=>x=5
since x can't be negative if the sum is positive and the product is positive.
y = 12-5=7
sum of reciprocal =1/7+1/5=5+7/35=12/35
hope it helped u .....mark as brainliest if u liked it.......
Now, A/q
x×y =35
=>x=35/y. (y is the second no.)
=>x=35/(12-x)=>12x-x^2-35=0
=>-x^2+12x-35=0
=>-x^2-7x-5x-35=0
=>-x(x+7)-5(x+7)=0
=>(x+7)(x-5)=0
=>x+7=0. or. x-5=0
= x=-7. or. x=5
=>x=5
since x can't be negative if the sum is positive and the product is positive.
y = 12-5=7
sum of reciprocal =1/7+1/5=5+7/35=12/35
hope it helped u .....mark as brainliest if u liked it.......
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