Question

here it is....................

Answer 1

In triangle ADC,

<ADC = 90°

<DAC = 45°

Now,

By angle sum property of triangle,

<ADC + <DAC + y = 180

=> 90 + 45 + y = 180

=> 135 + y = 180

=> y = 45°

Now,

In triangle BEC,

<BEC = 100°

<BCE = y = 45°

By angle sum property of triangle,

<BEC + <BCE + x = 180°

=> 100 + 45 + x = 180

=> 145 + x = 180

=> x = 35°

Now,

Let the point of intersection of AD and BE be O

In quadrilateral OECD,

<DOE + 90 + 100 + y = 360

=> <DOE + 190 + 45 = 360

=> <DOE + 235 = 360

=> <DOE = 360 - 235

=> <DOE = 125°

Now,

z = <DOE ( vertically opposite angles)

=> z = 125°