Question

Here M1 = 10kg nd M2= 6kg..g =10m/s^2
if the pulley is attached to the roof of a vehicle accelerating at 10m/s^2 in horizontal direction, what will be the acceleration of the masses , as seen by the observer in the vehicle?
A. 10√2 m/s^2
B. 10m/s^2
C. (2.5)√2 m/s^2
D. 2.5 m/s^2​

Answer 1

Answer:

The Accelration of the Masses is (d) 2.5m/s^2 .

Explanation:

According to Newton's Law of Motion, Acceleration can be calculated as:

$a=\frac{m_{2}-m_{1}}{m_{1}+x_{2}}g$

$=\frac{10kg-6kg}{6kg+10kg}(10m/s^2)\\=\frac{4kg}{16kg}(10m/s^2)\\=0.25(10m/s^2)\\=2.5m/s^2$  

Answer 2

Given:

M₁ = 10 kg

M₂ = 6 kg

g = 10 m/s²

To Find:

Acceleration of masses, a = ?

Solution:

According to Newton's Law of Motion,

⇒  $a=\frac{m_{2}-m_{1}}{m_{1}+x_{2}}\times g$

On putting the estimated values, we get

⇒     $=\frac{10-6}{6+10}\times 10$

⇒     $=\frac{4}{22}\times 10$

⇒     $=0.25\times 10$

⇒     $=2.5 \ m/s^2$

The acceleration will be "2.5 m/s²".