Question

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out of (2n+1)ticket consecutively numbers from 1 to 2n+1,three are drawn at random. find the probability that the number of them are in AP.

a)3n/4n^2+1
b)3n/4n^2-1
c)5n/6n^2-1
d)none of these

Answer 1

The answer for your question is b)3n/4n²-1
Use the condition for AP
i.e. common difference must be equal
d=a-a2=a3-a2=an-an-1
you will get the required answer.