Question

Here Projectile question for physics lovers! Kinematics! A body is projected from ground with speed u at an angle theta from horizontal. Find:- 1) Initial velocity 2.Velocity vector when body strikes on ground 3.velocity vector at topmost position 4.change in momentum between point of projection and touching the ground again

Answer 1

Given:

• initial speed = u
• angle = theta

1)

We know

• x component of a vector U= ucos$\theta$
• y component of vector U= usin$\theta$

Uvector= $\pink{(u \cos\theta \: ) i + (u \sin \theta )j}$-----i

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2.

Now clearly from the diagram,

Vvector=

$\pink{(u \: cos \theta) i - (u \: sin \: \theta) j}$----ii

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3.

At the top,

the vertical velocity will be zero or Uy=0

thus at top,

Vvector

= (Ux)i +(Uy)j

=(Ux)i

=$\blue{(u \: cos \: \theta) i}$

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4.

Momentum:

=m (Vfinal- Vinitial) [from equation i and ii]

=$\red{m( - 2u \: sin \: \theta) j}$

Answer 2

Explanation:hope you got your

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