Question

Here's a question....!
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An aeroplane flying horizontally 1 km above the ground is observed at an elevation of 60°.After 10 seconds, its elevation is observed to be 30°.Find the speed of the aeroplane in km/h.
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Answer 1

Hello!!

When the elevation was 60° distance of the point of observation to the point on the ground

below the plane = 1xcot60 = 1/3 km

Similarly when the angle becomes 30, distance becomes = 1xcot30 = 3 km

So, distance travelled = 3 -1/3 km = 2/3 km

time taken = 10sec = 10/3600 hr

hence speed = distance / time = 2x3600/10x3 = 720/3 km/hr = 415.7 km/hr

Answer 2

$\huge{\mathfrak{HEYA\:MATE\:!!}}$

Please refer to the attachment

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