Question

Here's A Question!!
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Solve the question from Circles (class 10) in the given attachment.
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No Spams!!​

Answer 1

from the figure

In triangle ABD

Angle DAB+Angle ABD +Angle ADB =180

65+70+Angle ADB

Angle ADB=45

Then angle D Becomes 90 as it is a semicircle

Hence AC is the diameter

Hope this helps you....

Answer 2

Step-by-step explanation:

given,

BAD = 65˚

ABD = 70˚

BDC = 45˚

(i) In ABD,

BAD + ABD + ADB

= 180˚

65˚ + 70˚ + ADB = 180˚ {Sum of three angles of a}

ADB = 180˚ – (65˚ + 70˚)

= 45˚

ADC = ADB + BDC

45˚ + 45˚ = 90˚

AC is the diameter of the circle.

[Angle in a semi circle is 90˚] Proved

(ii) ACB = ADB = 45˚

{Angles in the same segment of a circle}.

hope it helps...

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