Here's the most challenging puzzle of maths.
A A
+ B B
+ C C
= A B C
If AA+BB+CC=ABC
What are the values of A,B and C
(ANSWER ONLY IF YOU KNOW)
Answers
A = 1, b= 9, c= 8
Answer:
11+99+88=198
Step-by-step explanation:
AA+BB+CC=ABC
Substitute Maximum Posssible Values:
99+88+77=264
So,A is less than 300
(i.e.,) A is 1 or 2 (0 is not Possible because A,B,C are +ve numbers)
=====>Lets take Units digit:
A+B+C=C
A+B=0 (0 is a units digit)
Substitute A values:
1+B=0 or 2+B=0
1+9=0(10) or 2+8=0(10)
Above solution we get sum as 10 where 1 is a tens digit
and 0 is a units digit.
We get,
A=1 and B=9
(or)
A=2 and B=8
11+99+CC=19C (or) 22+88+CC=28C
110+CC=19C (or) 110+CC=28C 28C>264 (Maximum Possible
sum 99+88+77=264)
So,it is not Possible.
=======>Lets take Tens digit from 110+CC=19C:
1+C=9
C=8
Finally we get A=1 B=9 C=8
11+99+88=198
Easy Explanation In Puzzle Pedia:
https://www.youtube.com/watch?v=-fW8i5w5A2w
Puzzle Pedia Youtube Channel:
https://www.youtube.com/channel/UCVtK9k5zz-pgwX5Ah-wYiCQ
