Question

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A system of pulleys is used to lift a load of 1000 kg wt. If the efficiency of the pulley system is 80% and velocity ratio is 20, find the effort required to lift the load. Explain​

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Answer 1

Answer:

$⋆\huge\star\underline\mathtt\blue{AnsWer}$

Load ⇒ 1000kgwt

Efficiency ⇒ 80%

Velocity Ratio ⇒ 20

Effort ⇒ ?

⇒$</p><p>\sf \ Efficiency = \frac{Mechanical \ Advantage }{Velocity \ Ratio } Efficiency$

⇒ $\sf 0.8 = \frac{Mechanical \ Advantage }{20}0.8$

⇒ $\sf Mechanical \ Advantage = 0.8 \times 20Mechanical Advantage$

⇒$\sf Mechanical \ Advantage = 16Mechanical$

So now the question comes up that what is Mechanical Advantage?

⇒$\sf Mechanical \ Advantage = \frac{Load}{Effort}Mechanical Advantage$

⇒$\sf Effort = \frac{Load}{Mechanical \ Advantage }$

⇒ $\sf Effort = \frac{1000kgwt}{16}$

⇒ $\sf Effort = \frac{125}{2}$

⇒$\sf Effort = 62.5kgwt$

∴The effort required to lift the load would be 62.5kgwt.

Additional Information :)

What is velocity?

The rate of change of an object’s position with respect to a frame of reference and time is known as velocity.

What is the S.I unit of velocity?

S.I unit of velocity is m/s

What is mechanical advantage?

A calculation that measures the amplified force used up by a mechanical system is known as mechanical advantage.

What is the formula for mechanical advantage?

MA =$\dfrac{F_B}{F_A}$