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QUESTION :-
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1. Describe with the help of a circuit diagram the use of PN junction as a full wave rectifier.
2. A diode is connected to 200 volt AC main series with capacitor as shown. What is the final voltage across capacitor?
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( kuch aata jaata h nhi tm logon ko kya Yrr... Kuch bhi answer Dete ho =_= intermediate level questions h... Junior walemt answer kro.)
Answers
Answer:
2:- The diode D will conduct for positive half cycle of AC supply because this is forward biased. For negative half cycle of AC supply, this is reverse biased and does not conduct. So output would be half wave rectified and for half wave rectified output will V.
Answer:
Working:
The a.c input signal is fed to the primary (P) coil of the transformer. The p-region of both the diodes D
1
and D
2
are connected to two ends of secondary coil (S). The load resistance (R
L
) across which output voltage is obtained is connected between common point of n-regions of diodes and central topping of the secondary coil.
When positive half cycle of input a.c signal flows through the primary coil, induced emf is set up in the secondary coil due to mutual induction. The direction of induced emf is such that the upper end of secondary coil becomes positive while lower end becomes negative. Thus, D
1
diode is forward biased and D
2
is reverse biased. So, current through D
1
flows through circuit in a
Hope it will help you