Question

Here's Your "SwaggerGabru"

Harsh Pratap Singh :)

QUESTION :-
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Integrate the question given in attachment!!
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Note:-
Spammed answer will be deleted ⚠️
Giving copied answer is restricted ❎
Answer should be easy to understand.

(You guys just Spammed my every question whatever questions I asked in last hours are all wrong except few.)
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Answer 1

Answer

➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️

= (-5)*[(-6)+5]= x

= [(-30)+25] = x

= x = 30 - 25 ( all bracket open )

= x = 5 (☺answer☺)

jai siya ram☺ __/\__

➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️

¯\_(ツ)_/¯

Answer 2

$\tt \huge \red{answer : - } \\ \\ \sf \: \frac{4x + 1}{ \sqrt{ {2x}^{2} + x - 3 } } \\ \\ let \: {2x}^{2} + x - 3 = t \\ \\ diff \: \: both \: \: sides \: \: w.r.t.x. \\ \\ \sf \: 4x + 1 + 0 = \frac{dt}{dx} \\ \\ \sf \: dx = \frac{dt}{4x + 1} \: \\ \\ now \\ \\ \sf \int \: \frac{4x + 1}{ \sqrt{ {2x}^{2} + x - 3} } dx \\ \\ put \: \: the \: \: values \: \: of \: ( {2x}^{2} + x - 3) = t \: \: and \: dx \: \: = \frac{dt}{4x + 1} \\ \\ \sf \implies \int \: \frac{4x + 1}{ \sqrt{t} } \times \frac{dt}{4x + 1} \\ \\ \sf \implies \int \: \frac{1}{ \sqrt{t} } dt \\ \\ \sf \implies \int \: {t}^{ \frac{ - 1}{2} } dt \\ \\ \sf \implies \frac{ {t}^{ \frac{ - 1}{2} + 1} }{ \frac{ - 1}{2} + 1 } + c \\ \\ \sf \implies \frac{ {t}^{ \frac{1}{2} } }{ \frac{1}{2} } \: c \\ \\ \sf \implies {2t}^{ \frac{1}{2} } + c \\ \\ \sf \implies2 \sqrt{t} + c \\ \\ \sf \implies2 \sqrt{ {2x}^{2} + x - 3 } + c$