Question

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QUESTION :-
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A copper rod of length "L" rotates at an angular velocity ω in a plane perpendicular to a uniform field of magnetic induction B. Find the EMF developed between the ends of the rod.
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Answer 1

Answer:

☺HEY MATE HERE UR ANSWER☺

Motional EMF induced in a conductor of length L moving in magnetic field is given by equation

now lets take a small part of length "dx" which is at distance"x" from the hinge point

the speed of the point is given by

now the motional emf in that small part of the rod will be

so above is the induced EMF frm centre of rod to end ..

HOPE IT HELPS U☺

Answer 2

Answer:

The rod is supposed to be the combination of a number of infinitesimal elements. Speed of each element is different. Consider an element at a distance l from O. Speed of this element is ωl, and is perpendicular to its length.

⇒ε=∫vBdl, As v=ωl,ε=ωB∫

0L ldl= 21 ωBL 2

'O' turns out to be ′ + and P the ′− ′ve terminal.