Question

Here
Simplify.
4
i)
3 7
15 20
5
-​

Answer 1

Answer:

x = 2 is a root of given equation substitute x = 2 in L.H.S.

L.H.S. = 3(2)2 – 2k × 2 + 2m = 0

12 – 4k + 2m = 0

4k – 2m = 12 …(i)

Similarly when x = 2 is root of given equation

Substitute x = 3 in L.H.S.

L.H.S. = 3(3)2 – 2k × 3 + 2m = 0

27 – 6k + 2m = 0

6k – 2m = 27 …(ii)

On solving equations (i) and (ii), we get

k = 15/2 and m = 9