Question

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Take pie as A 180°

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Answer 1

$\huge \underline \mathfrak {Solution:-}$

We have to prove that,

$\tan(x) \tan( \frac{\pi}{3} - x ) \tan( \frac{\pi}{3} + x ) = \tan(3x)$

On taking LHS

$\tan(x) \tan( \frac{\pi}{3} - x ) \tan( \frac{\pi}{3} + x )$

On putting x = 180°

$\tan(x) \tan( \frac{180}{3} - x ) \tan( \frac{180}{3} + x ) \\ \\ = \tan(x) \tan(60 - x) \tan(60 + x)$

Now, by using identity

$\tan(y) \tan( 60 - y ) \tan( 60 + y ) = \tan(3y)$

LHS= tan3x

= RHS

Answer 2

Step-by-step explanation:

LHS= tan3x

= RHS........................