Question

HERE WE GO A FANTASTIC QUESTION

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the sum of Q terms of an ap is 63 Q - 3 q square if its Pth term is
- 60 find the value of P also find the 11th term of the AP
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STEP - BY - STEP EXPLAINATION NEEDED

Answer 1

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Answer 2

Given Sq = 63q-3q2 

S1 = 63 * 1 - 3* 1*1 

=60 = a1 sum of first 1 term is first term 

S2 = 63 * 2 - 3* 2 *2 

=114 

S2 - S1 = 114 - 60 

=54 = a2 Sum of first two terms - sum of first term is 2 nd term. 

SO , d = 54 - 60 = - 6 

Now, 

ap = - 60 

= a + (p-1) d = - 60 

= 60 + ( p-1) -6= - 60 

= p-1 = -60-60 / -6 

= p = 21 

Now, 

a11 = a+ 10 d 

=60 + 10 *-6 

= 60 + -60 

= 0