Question

here what is x value in this sum

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Answer 1

${(12)}^{2} = ({ \frac{1}{x}) }^{2} + {(37)}^{2} \\ ( { \frac{1}{x} })^{2} = {37}^{2} - {12}^{2} \\ { (\frac{1}{x} )}^{2} = 1369 - 144 \\ { (\frac{1}{x} )}^{2} = 1225 \\ \frac{1}{x} = \sqrt{1255 } \\ \frac{1}{x} = 35$

$x = \frac{1}{x} + \frac{1}{x} \\ = 35 + 35 \\ = 70$

u'r done!!

Thnx✌️♥️~

Answer 2

Answer:

note that In Triangle AOB h²=AB b²= OA and p²=OB