Question

heres the question

answer fast..pls​

Answer 1

using quadratic formula

n^2 - 2an +(a^2 - b^2)=0

n= 2a+- √(4a^2 - 4 a^2 + 4b^2)))/2

= 2a+- 2b)/2

= a+- b

= a+b , a- b

Answer 2

Answer:

Required roots of the given equation are a + b and a - b.

Step-by-step explanation:

Given equation is : x^2 - 2ax + ( a^2 - b^2 ) = 0.

From the properties of quadratic equations :

Roots of a quadratic equation ax^2 + bx + c = 0 are $\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$ , used variables are different from the variables given in the question.

On comparing the given equation with ax^2 + bx + c = 0 we get

= > x = [ - ( - 2a ) ± √{ ( - 2a )^2 - 4( a^2 - b^2 ) } ] / 2( 1 )

= > x = [ 2a ± √( 4a^2 - 4a^2 + 4b^2 ) ] / 2

= > x = [ 2a ± √( 4b^2 ) ] / 2

= > x = ( 2a ± 2b ) / 2

= > x = a ± b

Hence the required roots of the given equation are a + b and a - b.