heres the question
answer fast..pls
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using quadratic formula
n^2 - 2an +(a^2 - b^2)=0
n= 2a+- √(4a^2 - 4 a^2 + 4b^2)))/2
= 2a+- 2b)/2
= a+- b
= a+b , a- b
vaishnavitiwari1041:
thank u
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Answer:
Required roots of the given equation are a + b and a - b.
Step-by-step explanation:
Given equation is : x^2 - 2ax + ( a^2 - b^2 ) = 0.
From the properties of quadratic equations :
Roots of a quadratic equation ax^2 + bx + c = 0 are , used variables are different from the variables given in the question.
On comparing the given equation with ax^2 + bx + c = 0 we get
= > x = [ - ( - 2a ) ± √{ ( - 2a )^2 - 4( a^2 - b^2 ) } ] / 2( 1 )
= > x = [ 2a ± √( 4a^2 - 4a^2 + 4b^2 ) ] / 2
= > x = [ 2a ± √( 4b^2 ) ] / 2
= > x = ( 2a ± 2b ) / 2
= > x = a ± b
Hence the required roots of the given equation are a + b and a - b.
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