Question

hermitian operators have real Eigen values.Explain.​

Answer 1

Answer:

The eigenvalues of a Hermitian operator are real. (This means they represent a physical quantity.) ... PROVE: The eigenfunctions of a Hermitian operator can be chosen to be orthogonal. Show that, if B F = s F & B G = t G & t is not equal to s, then <FG> = 0.

Explanation:

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