hetan had some money in his pockect.he spent 60% of it in buying groceries. if the remaining amount with him was ₹240, then how much did he have in the beginning?
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Answered by
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According to the information,
40 /100*x=240
X=240*100/40
X=600rs.
X is the money he had initially.
40 /100*x=240
X=240*100/40
X=600rs.
X is the money he had initially.
Answered by
0
We have to find how much Hetan had money in the beginning.
So let Hetan had x in the beginning.
Given that he spent 60% of it in groceries.
We know that total percent can be 100% so if he spent 60% then remaining percent will be (100%-60%) or 40%.
So now Hetan have 40% of the original money (x).
which is 0.40x.
Given that now he has 240 rupee.
So that means both are equal and give equation
0.40x=240
x=240/0.40
x=600
Hence the final answer is 600 rupees.
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