Math, asked by dhruvi5094, 1 year ago

hetan had some money in his pockect.he spent 60% of it in buying groceries. if the remaining amount with him was ₹240, then how much did he have in the beginning?

Answers

Answered by brainlyvis
0
According to the information,
40 /100*x=240
X=240*100/40
X=600rs.
X is the money he had initially.
Answered by lublana
0

We have to find how much Hetan had money in the beginning.

So let Hetan had x in the beginning.

Given that he spent 60% of it in groceries.

We know that total percent can be 100% so if he spent 60% then remaining percent will be (100%-60%) or 40%.

So now Hetan have 40% of the original money (x).

which is 0.40x.

Given that now he has 240 rupee.

So that means both are equal and give equation

0.40x=240

x=240/0.40

x=600

Hence the final answer is 600 rupees.

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