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Solution:
The perimeter of ∆PBC = PC + PB + BC
= PC + PB + BX + CX
But Cx = CR and BX = BQ [Since, tangents drawn from an external point]
Therefore, PC + PB + BQ + CR = (PC + CR) + (PB + BQ)
= PR + PQ
= 7 + 7 [Since PR = PQ tangents drawn from an external point]
= 14 cm
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