hey..
50 points. .solve this with explanation
Attachments:
Answers
Answered by
0
Answer:
Step-by-step explanation:
PQ=10CM
QR=10CM
Ф/360*πr²-1/2 *r²*SINФ
1100/21 -25√3
bhaveshvk18:
y 1/2*r^2*sin@
explain it..
SINCE THEIR ARE TWO RADII AND QR IS 10 CM THEY FORM EQUILATERAL TRIANGE THERFORE @IS 60 AND THE FORMULA YOU IS SEEING IS DIRECT METHORD OF FINDING AREA OF SECTOR
WEST OF LUCK
SOORY
SORRY BEST OF LUCK
OK
hmm..
thanks..
but still have a doubt
Answered by
0
Answer:
Step-by-step explanation:
QR = 1O CM
PQ = 10 CM
THEREFORE, PR = 10 CM (All radii of a circle are equal in length)
PQR IS A TRIANGLE
AREA OF A TRIANGLE = 1/2 * BASE * HEIGHT
= 1/2 * 10 * 10
= 50 CM²
AREA OF THE SEGMENT = AREA OF SECTOR - AREA OF TRIANGLE
I HAVE GIVEN YOU AN IDEA GO IT AND TRY IT OUT
Similar questions