Question

hey❤
A ball is dropped from the top of a tower of height h. It covers a distance h/2 in the last second. How long does the ball remain in air​

Answer 1

Answer:

For total journey

H = 0.5gT^2 ……[1]

For 1st half journey

H/2 = 0.5g (T - 1)^2 ……[2]

Divide equation [1] with [2]

H / (H/2) = [T / (T - 1)]^2

2 = [T / (T - 1)]^2

√2 = T / (T - 1)

T√2 - √2 = T

T (√2 - 1) = √2

T = √2 / (√2 - 1)

T = 1.414 / 0.414

T = 3.4 s