Math, asked by choudhary21, 5 months ago

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A takes twice as much time as B and C together take to finish the job. A and B working together finish the job in 4 days. C alone can do the same job in 4 days. In how many days can B alone do the same job?​


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Answers

Answered by rinkughosh9932
40

Answer:

A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in,... So, B takes (12/2) = 6 days to finish the work.

Step-by-step explanation:

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Answered by zarathequeen
9

Step-by-step explanation:

Ritanjali Natua said: (Jun 28, 2010)

1/x+2/x+3/x=6/x

Meera said: (Sep 13, 2010)

A+B+C's 1 days work is = 1/6.

Therefore 2'days work (A+B+C) is=1/6*2=3.

B can do the work alone (2*3) =6.

So B takes 6 days to finish the work.

Is it right method? please anyone tell me.

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