Question

Hey !!!

An interesting question for you guys ☺.

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A policy Jeep is chasing a culprit going on a motorbike . the moterbike crosses a turning at a speed of 72km/h. the jeep follows it at a speed of 90km/h , crossing the turning ten seconds later than bike . Assuming that they travel at constant speeds , How far from the turning will the Jeep catch up with bike ?
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Answer 1

The speed of police jeep = 90 km/h = 25 m/s

speed of the motorbike = 72 km/h = 20 m/s

Before the Jeep reaches the turning, the motorbike would have travelled some distance.

Distance travelled by the motorbike in 10 seconds = 20 x 10 = 200 metres

Now, when the police jeep reaches the turning, the culprit is 200 metres ahead of him.

Let the culprit be caught at a distance 'h' from the turning and at a time 't'

Now, distance to be travelled by the jeep = h

→ h = 25t

→ t = h/25 --------------> 1

Also, distance to be travelled by the culprit = h - 200

→ h-200 = 20t

→ t = (h-200)/20 --------------> 2

Equating both equations 1 and 2, we get

→ h/25 = (h-200)/20

→ 20h = 25h - 5000

→ 5h = 5000

→ h = 1000 metres

Therefore the Jeep will catch up with the bike after travelling 1 km from the turning.

Hope it helps!!

Answer 2

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