Question

hey another question help​

Answer 1

Answer of 2

x2 + x - p (p+1)

2x square + p2+ p

2x square + 2p square

Answer of 3

x2- 3x - m(m+3)

x - 3 - m2 + 3m

x - 3 - m + 3

Answer 2

Answer:

$answer$

Given polynomial equation x2+x-p (p+1)

x2+x-p(p+1)=0

On factorising we get,

x2+(p+1)x-px-p(p+1)=0

x(x+p+1) -p(x+p+1)=0

(x+p+1)(x-p)=0

x=-p-1, and x= p

The zeros of polynomial are: p-1 and p