Hey another question.. solve it please
2nd part
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Hey ❗❗
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➡Refer to the attachment !! _______________________
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Rishab256:
thx..
Answered by
4
Hello Friend...
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The answer of u r question is...
Lim [sin (π-x)]
x (π-x)
= Lim. 1. Lim. sin (π-x)
----------. -----. -------- -------
x-->. π. x. x+π. π-x
= 1. Lim. sin t
------ --------. = --------
x. t-->0. t
= 1 1
-------. (1). = ------
π. π
___________________________
___________________________
Thank you..⭐️⭐️⭐️
_______________________
_______________________
The answer of u r question is...
Lim [sin (π-x)]
x (π-x)
= Lim. 1. Lim. sin (π-x)
----------. -----. -------- -------
x-->. π. x. x+π. π-x
= 1. Lim. sin t
------ --------. = --------
x. t-->0. t
= 1 1
-------. (1). = ------
π. π
___________________________
___________________________
Thank you..⭐️⭐️⭐️
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