Question

hey... ans

5L N2 and 5L H2 r allowed 2 react
The substance n it's no. Of mole remain unreacted is ​

Answer 1

Answer:

0.074 moles

Explanation:

The equation of the reaction is

2N₂+ 3H₂ --------> 2NH₃

initial no of moles of N₂=5/22.4=0.223

initial no of moles of H₂=5/22.4=0.223

From the above equation we see that 2 moles of N₂ react with 3 moles of H₂

Therefore the limiting agent is H₂

Hence moles of N₂ remain unreacted

No of moles of N₂ consumes can be found out by using the unitary method or by the standard procedure done.

no of moles of N₂ consumed=

=(coefficient of N₂ in reaction * no of moles of H₂ taken)/coefficient of H₂ in the reaction

Plugging in the values

=(2*5/22.4)/3

=0.149

No of moles of N₂ left=0.223-0.149

=0.074 moles

hope this helps