Chemistry, asked by Anonymous, 3 months ago

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Answered by happygirl4984
22

Answer:

Please mark as brainliest

Explanation:

1.(p - 11) * (p - 11) equals p * (p - 11) - 11 * (p - 11)

that equals p^2 - 11p - 11p + 121

combine like terms to get p^2 - 22p + 121

the expression (p - 11) * (p - 11) is equivalent to the expression p^2 - 22p + 121.

if you graph both those equations (by replacing p with x), you will find that both equations draw the same, identical graph.

Answered by raghavendras1973
0

Answer:

ANSWER

(a) (p - 11)(p + 11) = p^2 - 121

(b) (2y + 5)(2y - 5) = 4y^2 - 25

(c) (12a - 9)(12a + 9) = 144a^2 - 81

(d) (2a - 1/2)(2a - 1/2) = 4a^2 - 2a + 1/4

(e) (1.1m - 0.4)(1.1m + 0.4) = 1.21m^2 - 0.16

(f) (a ^ 2 + b ^ 2)(- a ^ 2 + b ^ 2) = -a^4 + b^4

(g) (6x - 7)(6x + 7) = 36x^2 - 49

(h) (- a / 2 + c / 2)(- a / 2 + c / 2) = (a^2 - 2ac + c^2) / 4

(i) [(p / 8) + (3q / 4)][(p / 8) + (3q / 4)] = (p^2 / 64) + (3pq / 16) + (9q^2 / 16)

(j) (3a + 9b)(3a - 9b) = 27a^2 - 81b^2

(k) 2 * (a - 9) ^ 2 = 2a^2 - 36a + 162

(l) 5 * (xy - 3z) ^ 2 = 5x^2y^2 - 30xyz + 45z^2

(m) (6x + 5y) ^ 2 = 36x^2 + 60xy + 25y^2

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