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A space craft is moving vertically upwards . An object is dropped from
it at an instant where its velocity is 4.9ms^-1. If the object reaches the earth after 2 seconds then the final velocity of the object is what? (g=9.8ms^-1)
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u for the ball will be equal to 4.9m/s as u is equal to velocity of air craft at the instant of dropping the ball.
g= 9.8m/s^2
t= 2 secs
now, according to v= u+ at
v= 4.9-9.8(2)
v=4.9-19.6
v=-14.7m/s
Explanation:
Anonymous:
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Answered by
0
Answer:
14.7
Explanation:
u=-4.9
a=g=9.8
t=2
v=u+at
=-4.9+9.8x2
=-4.9+19.6
v= 14.7m/s
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