Math, asked by singhrinki017, 5 months ago

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Answered by sethrollins13
28

Given :

  • Ages of Asha and Sushma are in the ratio 7:2.
  • After 8 years their ages will be in ratio 5:2.

To Find :

  • Present Age of Asha and Sushma.

Solution :

\longmapsto\tt{Let\:Present\:Age\:of\:Asha=7x}

\longmapsto\tt{Let\:Present\:Age\:of\:Sushma=2x}

After 8 years :

\longmapsto\tt{Age\:of\:Asha=7x+8}

\longmapsto\tt{Age\:of\:Sushma=2x+8}

A.T.Q :

\longmapsto\tt{\dfrac{7x+8}{2x+8}=\dfrac{5}{2}}

\longmapsto\tt{2(7x+8)=5(2x+8)}

\longmapsto\tt{14x+16=10x+40}

\longmapsto\tt{14x-10x=40-16}

\longmapsto\tt{4x=24}

\longmapsto\tt{x=\cancel\dfrac{24}{4}}

\longmapsto\tt\bf{x=6}

Value of x is 6...

Therefore :

\longmapsto\tt{Present\:Age\:of\:Asha=7(4)}

\longmapsto\tt\bf{28\:yrs.}

\longmapsto\tt{Present\:Age\:of\:Sushma=2(4)}

\longmapsto\tt\bf{8\:yrs.}

Answered by aviguru111
3

Answer:

Given :

Ages of Asha and Sushma are in the ratio 7:2.

After 8 years their ages will be in ratio 5:2.

To Find :

Present Age of Asha and Sushma.

Solution :

\longmapsto\tt{Let\:Present\:Age\:of\:Asha=7x}

\longmapsto\tt{Let\:Present\:Age\:of\:Sushma=2x}

After 8 years :

\longmapsto\tt{Age\:of\:Asha=7x+8}

\longmapsto\tt{Age\:of\:Sushma=2x+8}

A.T.Q :

\longmapsto\tt{\dfrac{7x+8}{2x+8}=\dfrac{5}{2}}

\longmapsto\tt{2(7x+8)=5(2x+8)}

\longmapsto\tt{14x+16=10x+40}

\longmapsto\tt{14x-10x=40-16}

\longmapsto\tt{4x=24}

\longmapsto\tt{x=\cancel\dfrac{24}{4}}

\longmapsto\tt\bf{x=6}[/tex[</p><p></p><p>[tex]Value\: of \:x \:is \:6...

Therefore :

\longmapsto\tt{Present\:Age\:of\:Asha=7(4)}

\longmapsto\tt\bf{28\:yrs.}

\longmapsto\tt{Present\:Age\:of\:Sushma=2(4)}

\longmapsto\tt\bf{8\:yrs.}

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