Question

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Answer 1

Explanation:

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Answer 2

Hi there,

Here is your answer

We know that A.M ≥ G.M

⇒ Min value of AM is obtained when AM=GM

⇒The quantities whose AM is being taken are equal.

(i.e) cos(α+π/2)=cos(β+α/2)=cos(γ+π/2)

-sinα=-sinβ=-sinγ  {cos(α+π/2)=-sinα}

⇒sinα=sinβ=sinγ

Also α+β+γ=360∘

⇒α=β=γ=120∘

=2π/3  {120∘ =2π/3}

∴ Minimum value of A.M=cos(2π/3+π/2)+cos(2π/3+π/3)+cos(2π/3+π/2)3

⇒−sin2π/3÷3

⇒−3/√2 Ans

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