Question

Hey answer this

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Answer 1

Explanation:

Hia buddy... .......

Here's your answer.....

Given:

Given:n = 50% = 50/100 = 0.5

Given:n = 50% = 50/100 = 0.5n' = 70% = 70/100 = 0.7

Given:n = 50% = 50/100 = 0.5n' = 70% = 70/100 = 0.7t2 = 7°C = 280°K

Answer

By using formula,

$n = \frac{t1 - t2}{t1}$

0.5 = t1 - 280/t1

t1 = 560°K

Now using same formula again!

$n = \frac{t1 - t2}{t1}$

0.7 = t1' - 280/t1'

t1' = 933°K

So ∆T = t1'-t1 = 933 - 560

So ∆T = t1'-t1 = 933 - 560 = 373 ~ 380°K

Hope it helps uh!