hey!!! any 1 who could help me to solve this question...
if 2 and -3 are the zeroes of the quadratic polynomial x²+(a+1) x+b, then find the value of a and b.
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answer of this question a= 0 and b= -1
Answered by
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Hi.....
Here is your answer friend :-)
x2-(a+1) x+b=0
(2)2-(a+1)2+b=0
4-2a+2+b=0
2a+b=-2--------(1)....
(-3)2-3a-3+b=0
-6-3a-3+b=0
-3a+b=9----------(2).....
On solving 1 and 2
a=-11/5
b=12/5.
Hope helpful pls mark as brainlist :-):-)
Here is your answer friend :-)
x2-(a+1) x+b=0
(2)2-(a+1)2+b=0
4-2a+2+b=0
2a+b=-2--------(1)....
(-3)2-3a-3+b=0
-6-3a-3+b=0
-3a+b=9----------(2).....
On solving 1 and 2
a=-11/5
b=12/5.
Hope helpful pls mark as brainlist :-):-)
shuzu:
thnx bhayya...
please mark as brainlist friend :-):-)
ok
thanks :-):-)
my pleasure ^-^
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