Question

hey anybody solve this plz...​

Answer 1

answer

${ \large \bold \orange { \underline{answer \: \: \: x = \frac{ - 18}{7} }}}$

Step-by-step explanation:

$\mathfrak{ \large \bold \red { \underline { \underline{question}}}} \\ \\ { \large \bold{( \frac{ {a}^{3} }{ {b}^{3}} ) {}^{2x + 4} = ( \frac{ {b}^{2} }{ {a}^{2} } )}} {}^{ \frac{x}{2} + 3} \\ \\ { \large \bold \blue { \underline {solution}}} \\ { \large{( \frac{a}{b}) {}^{3(2x + 4)} = ( \frac{b}{a} ) {}^{2( \frac{x}{2} + 3)} }} \\ { \large{( \frac{a}{b}) {}^{6x + 12} = ( \frac{a}{b} ) {}^{ - 2( \frac{x}{2} + 3)} }} \\ { \large{( \frac{a}{b}) {}^{6x + 12} = ( \frac{a}{b} ) {}^{ - x - 6} }} \\ { \large{6x + 12 = - x - 6}} \\ { \large{7x = - 18}} \\{ \large{x = \frac{ - 18}{7} }} \\ \\ \\ { \large \bold \orange { \underline{answer \: \: \: x = \frac{ - 18}{7} }}}$

Answer 2

Step-by-step explanation:

$x = \frac{ - 18}{7}$