Question

✨✨Hey Brainiacs! ✨✨

Solve this .....

find the perimeter of triangle if its area is 9 cm^2 and perpendicular ² + breadth² is 45.

Answer 1

Given,

Area of traingle = $\frac {1}{2} Base * height$

$\implies$ 1/2 × base × height = 9

$\implies$ base × height = 18

As , given

$\implies$ perpendicular ² + base² = 45


$\implies$ Apply, (P + B )² = p² + B² + 2B× H

$\implies$ (P + B)² = 45 + 2(18)

$\implies$(P + B)² = 45 + 36

$\implies$ (P + B)² = 81

$\implies$ (P + B) = √81 = 9

$\implies$ So, Here we have to check the digits which makes sum 9

➡ 6 and 3 = 9

$\implies$ Probably 6 and 3 are its base and perpendicular of the traingle.

Answer 2

Answer:

Area of traingle = \frac {1}{2} Base * height

2

1

Base∗height

\implies⟹ 1/2 × base × height = 9

\implies⟹ base × height = 18

As , given

\implies⟹ perpendicular ² + base² = 45

\implies⟹ Apply, (P + B )² = p² + B² + 2B× H

\implies⟹ (P + B)² = 45 + 2(18)

\implies⟹ (P + B)² = 45 + 36

\implies⟹ (P + B)² = 81

\implies⟹ (P + B) = √81 = 9

\implies⟹ So, Here we have to check the digits which makes sum 9

➡ 6 and 3 = 9

\implies⟹ Probably 6 and 3 are its base and perpendicular of the traingle.