Question

Hey brainliess, i need some help here ​

Answer 1

Solution:-

put x=sin theta

$\implies \sin {}^{ - 1} (2x \sqrt{1 - x {}^{2} } )$

$\implies \sin {}^{ - 1} (2 \sin \theta \sqrt{1 - { \sin }^{2} \theta } ) \\ \\ \implies \: \sin {}^{ - 1}(2 \sin \theta \cos \theta ) \\ \\ \implies \: \cancel{ \sin {}^{ - 1}} ( \cancel{\sin}2 \theta ) \\ \\ \implies \: 2 \sin \: {}^{ - 1}x \\ \\ \implies \: 2( \frac{\pi}{2} - \cos {}^{ - 1}x) \\ \\ \implies \: \pi - 2 \cos {}^{ - 1} x$

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thanks