Hey brainliess!!
plz solve this question
a^3 + b^3 + 1 -3ab
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Answer:
Given,
a + a = 2
2 a = 2
Dividing both the sides by 2;
2a / 2 = 2 / 2 = 1
Therefore,
a = 1
Now, it is also given,
a + b = 3
Substituting the value of a = 1
1 + b = 3
b = 3 - 1
b = 2
Therefore , b = 2
Also, It is given :
a + b + c = 6
Substituting value of a and b
1 + 2 + c = 6
3 + c = 6
c = 6 - 3
c = 3
We need to find value of :
a + b + c * 4
Substituting values of a , b and c
= 1 + 2 + 3 * 4
= 1 + 2 + 12
= 3 + 12
= 15
Hence,
The answer is 15
Step-by-step explanation:
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