hey brainly users..!!
help me with this class 11th physics question:
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a wire is stretched by the application of 50 kg wt/ sq. cm. what is the percentage increase in the length of the wire? y = 7 into 10^10 N/m^2, g = 9.8 m/s^2
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Answers
Answered by
1
Hi friend here is your answer
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Data
Stress = 50 kg wt / sq cm
= 50 X 9.8 X 10 raise to 4(m sq)
Youngs Modulus = 7 X 10 raise to 10
To find
The PERCENTAGE ELONGATION
Y = Stress / Strain
Strain = stress /Y
= 50 X 9.8 X 10 raise to 4 / 7 X
10 raise to 10
= 7 X 10 raise to - 5
Percentage elongation = Strain X 100
= 7 X 10 raise to - 5 X100
= 0.007%
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Answered by
2
Hey !!
Given,
Stress = 50 kg wt/ sq. cm ( It can be conveted into 50 × 9.8 m/s² / 10⁻⁴ m²
=> 50 × 9.8(10⁴) N/m²
→ Y = 7 × 10¹⁰ N/m²
→ g = 9.8 m/s²
→ NOTE :- (g) value it can be either 9.8 m/s² (or) 10 m/s²
We know that,
Y(Young's modules of elasticity) = Stress/Strain
Strain → Stress/Y ⊕ Strain = 7 × 10⁻⁵
= 50 × 9.8 × 10⁴ / 7 × 10¹⁰
Elongation = Strain × 100
= 7 × 10⁻⁵ × 100
Percentage Elongation = Strain × 100
= 0.007
ANSWER :- 0.007
locomaniac:
thanks man... ^^
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