Physics, asked by locomaniac, 1 year ago

hey brainly users..!!
help me with this class 11th physics question:

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a wire is stretched by the application of 50 kg wt/ sq. cm. what is the percentage increase in the length of the wire? y = 7 into 10^10 N/m^2, g = 9.8 m/s^2

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thank you :)

Answers

Answered by Theusos
1

Hi friend here is your answer


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Data


Stress = 50 kg wt / sq cm

= 50 X 9.8 X 10 raise to 4(m sq)


Youngs Modulus = 7 X 10 raise to 10

To find


The PERCENTAGE ELONGATION


Y = Stress / Strain



Strain = stress /Y

= 50 X 9.8 X 10 raise to 4 / 7 X

10 raise to 10


= 7 X 10 raise to - 5


Percentage elongation = Strain X 100


= 7 X 10 raise to - 5 X100

= 0.007%


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Hope it helps you.............!!

#TheUsos

Down since

Day One Ish



Answered by nalinsingh
2

Hey !!

Given,

                 Stress = 50 kg wt/ sq. cm ( It can be conveted into 50 ×  9.8 m/s² / 10⁻⁴ m²

                  => 50 × 9.8(10⁴) N/m²

                    → Y = 7 × 10¹⁰ N/m²

                    → g = 9.8 m/s²

→ NOTE :- (g) value it can be either 9.8 m/s² (or) 10 m/s²

We know that,

Y(Young's modules of elasticity) = Stress/Strain

    Strain     → Stress/Y                     ⊕ Strain =  7 × 10⁻⁵

           = 50 × 9.8 × 10⁴ / 7 × 10¹⁰  

       Elongation = Strain × 100

        = 7 × 10⁻⁵ × 100

Percentage Elongation = Strain × 100

             = 0.007

ANSWER :- 0.007


locomaniac: thanks man... ^^
Haezel: `great
nalinsingh: Thank you Mahika and Mam :-)
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