Hey brainy stars !!
Prove that 2+2=5
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please don't write foolish answers
Answers
Hey there !
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Given : 2 + 2 = 4 .............(1)
To prove : 2 + 2 = 5
Proof :
We can say that..
20 - 20 = 25 - 25
[Because both equals to 0]
20 - 20 = 25 - 25
5 × 4 - 5 × 4 = 5 × 5 - 5 × 5
4 ( 5 - 5 ) = 5 ( 5 - 5)
On cancelling [ 5 - 5 ] both sides..
∴ 4 = 5
Now,
As we have proved above : 4 = 5
We can substitute value in equation (1)
2 + 2 = 4 [ Given ]
=> 2 + 2 = 5 [ 4 = 5 ]
Hence,
It is proved that 2 + 2 = 5
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Now, coming to the mistakes that we have done above, because it is universal truth that
[ 2 + 2 = 4 ]
So, in the above solution we can't cancel 5 - 5 both sides because both the sides , there are different numbers multiplied.
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Hope you are satisfied.
Thanks for the question !
☺☺☺
⚫ Here is ur answer⬇⬇⬇
⭐ To Prove :
▶ Starts with : -20 =-20
▶ which is the same as : 16 - 36 = 25 - 45
▶ Which also express as : 2+2
2(9× ( 2+2 ) = 52 ) 9×5
⭐: Shock :⭐
⭐ Must have been written as : (2+2)² - 9×(2+2) = 5² - 9×5
▶Add 81/4 to both sides :( 2+2 ) 2 (9 × (2+2) + 81/4
Must have been written as : (2+2)² - 9× (2+2) + 81/4 = 5² - 9×5 + 81/4
▶ Rearrange the terms : ({2+2}) 9/2) 2 = (5-9/2) 2
⭐ Must have been written as : ((2+2) - 9/2)² = (5 - 9/2)²
⚫ [step a]
▶Ergo: 2+2 -9/2 = 5
⭐ Must have been written as: (2+2) -9/2 = 5 -9/2
⚫ [step b]
▶ HENCE :➡ 2+2 = 5
⭐⭐ Wow we discover What ⭐⭐
(-1/2)²= (1/2)²but -1/2 <> 1/2 ( step a and b)
▶Let x be a none zero number and set y=x Thus:
x = y
x^2 = xy
x^2 - y^2 = xy - y^2
(x+y) (x-y) = y(x-y)
x+y = y
2y = y
2 = 1
1 = 0
⭐Now since 2+2 = 2+2+0 and we apply the lemma proof so that 0 = 1 , 2+2+0 = 2+2+1 = 5
THEREFORE = 2+2 =5 }[/tex]
HOPE IT HELPS.
CHEERS!!!