hey can any one help me
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take triangle ABC rt angled at B and angke theta at A
then according to pythagorus theorum find BC the perpendicular as 3 units
then sin teta wud be 3/5 cos theta=4/5 tan theta = 3/4 and cot theta=4/3
then put the values
2×4/5 -3/5 upon 4/3-3-4
u wud get
5/5 upon 7/12
take 7/12 in the numerator so it wud become 12/7
then according to pythagorus theorum find BC the perpendicular as 3 units
then sin teta wud be 3/5 cos theta=4/5 tan theta = 3/4 and cot theta=4/3
then put the values
2×4/5 -3/5 upon 4/3-3-4
u wud get
5/5 upon 7/12
take 7/12 in the numerator so it wud become 12/7
shreya2011:
in that gx polynomial one its not clear
is the no. 13 or 3
yes its gx
arre its 13 or k?
its k
g(x)=x2-2x+k
I wud surely solve ur ques within 10min
kk
thank u so much frd
ur wlcm
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@Laughterqueen
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