Question

Hey! Can anybody solve Q36 and Q37 with step-by-step solution?
Thanks!

Answer 1

Let x be the total capital.Hence she invested x/3 at 7% interest.x/4 at 8% interest  and remaining 5x/12 at 10% interest.

Interset=ptr/100(p=priciple amount;t=time;r=rate)

for 1 year her income for this capital will is 561

561=[(x/2)*1*7/100]+[(x/4)*1*8/100]+[(5x/12)*1*10]/100

from this we get x i.e., total capital is which is approximately equal to 5800/-