Question

hey can someone answer this please
ch compound interest
find the amount and the compound interest on rupees 42000 find 1 year at 18%p.a compounded half yearly ​

Answer 1

Answer:

Amount= Rs. 49560

Compound Interest= Rs. 7560

Step-by-step explanation:

P= Rs. 42000

n= 1 year

R= 18%

A= P (1+R/100)^n

= 42000 (1+18/100)^1

= 42000 (1+9/50)^1

= 42000 (50+9/50)^1

= 42000 x 59/50

= 840 x 59

= Rs. 49560

Compound Interest= A-P

= Rs. (49560-42000)

= Rs. 7560

Answer 2

Answer:

compound interest is Rs.7900.2

Step-by-step explanation:

• principal = Rs.42000
• Rate of interest = 18%
• time = 1 yr

$\: a =p(1 + \frac{r }{100 \: } \: ) {2}^{number \: of \: years \: }$

$= 42000(1 + \frac{18}{200} ) {2}^{n}$

$= 42000(200 + \frac{18}{200} ) {2}^{n}$

$= 42000 \times \frac{218}{200} \times \frac{218}{200}$

$= 21 \times \frac{109}{10} \times 218$

$= \frac{499002}{10}$

$a = 49900.2$

now compound interest = A - P.

$49900.2 - 42000.0 = 7900.2$

so , here is the required answer.